来诈金花嘛？Python实现的那种

前言

《诈金花》又叫三张牌，诈金种是实现在全国广泛流传的一种民间多人纸牌游戏。比如JJ比赛中的诈金种诈金花(赢三张)，具有独特的实现比牌规则。游戏过程中需要考验玩家的诈金种胆略和智慧。--《百度百科》 前几天在交流群里边，实现有个叫【^-^】的诈金种粉丝分享了一道扑克牌诈金花的题目，要求用Python实现，实现题目如下：

自己写一个程序，诈金种实现发牌、实现比大小判断输赢。诈金种

#### 游戏规则：

一付扑克牌，实现去掉大小王，诈金种每个玩家发3张牌，实现最后比大小，诈金种看谁赢。

有以下几种牌：

豹子：三张一样的牌，如3张6.

顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7

顺子：又称拖拉机，花色不同，但是顺子，源码库如红桃5、方片6、黑桃7，组成的顺子

对子：2张牌一样

单张：单张最大的是A

这几种牌的大小顺序为， **豹子>顺金>顺子>对子>单张

**#### 需程序实现的点：一、思路

针对这个问题，首先需要构造一副扑克牌，根据扑克牌的属性特征，进行不断的拆解，然后构造玩家用户，这里经常会用到字典和列表来存储信息，屡试不爽。

二、解决方案

针对该问题，粉丝【^-^】给出了解决方法，直接上代码如下：

# -*- coding: utf-8 -*-

import random

puke = [] # 存储扑克牌

num_list = [2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A]

hua_list = [梅花, 红桃, 黑桃, 方块]

sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4, 7: 5, 8: 6, 9: 7, 10: 8, J: 9, Q: 10, K: 11, A: 12,

对子: 15, 顺子: 30, 顺金: 60, 豹子: 100}

count_new_list = [] # 存储玩家分数和排序后排名

count_dic = { } # 存储玩家分数

# 准备52张扑克

for hua in hua_list:

for num in num_list:

a = hua + num

puke.append(a)

player_dic = { 玩家1: [], 玩家2: [], 玩家3: [], 玩家4: [], 玩家5: []}

# 随机给五个玩家发牌

# print(len(puke))

for key, value in player_dic.items():

for i in range(3):

plate = random.sample(puke, 3)

player_dic[key] = plate

for i in plate:

puke.remove(i)

print(player_dic)

# 获取玩家的牌型

def paixing(list1):

num = []

huase = []

for i in list1:

a = i[2:]

b = i[:2]

num.append(a)

huase.append(b)

return num, huase

# sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4}

# 对数字的牌型进行排序

def sort(num):

new_num = []

sort_list2 = []

list1 = []

for i in num:

new_num.append(sort_dic[i])

new_num = sorted(new_num) # 排序后是[2, 4, 7]

for new in new_num:

sort_list2.append([k for k, v in sort_dic.items() if v == new])

for m in sort_list2:

for n in m:

list1.append(n)

return list1

# 对玩家的牌形统计分数

def count(num, huase):

a = 0

base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]

if num[0] == num[1] and num[1] == num[2]:

paixing = 豹子

a = base_count + sort_dic[paixing]

elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[

1] and huase[1] == huase[2]):

paixing = 顺金

a = base_count + sort_dic[paixing]

elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (

huase[0] != huase[

1] or huase[1] != huase[2]):

paixing = 顺子

a = base_count + sort_dic[paixing]

elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (

num[0] == num[2] and num[1] != num[0]):

paixing = 对子

a = base_count + sort_dic[paixing]

else:

a = base_count

return a

# 对存储玩家分数的字典进行排序

def compare(count_dic):

d = list(zip(count_dic.values(), count_dic.keys()))

return sorted(d, reverse=True)

for key, value in player_dic.items():

num, huase = paixing(value)

num = sort(num)

count1 = count(num, huase)

count_dic[key] = count1

print(key + "的牌为：" + str(value))

count_new_list = compare(count_dic)

# print(count_new_list)

print(最终排名： + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][

1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")

代码看上去确实挺多的，超过了100行，需要花点时间去读，不过涉及的云服务器知识点并不复杂，基本上有点Python基础，也可以理解。代码运行之后，可以看到效果如下：

不过后来我在读取这份代码的时候，发现中间有个地方写的着实有些冗余，稍微修改下，代码方面简洁一些，一些函数和变量命名加了一些对应的现实意义的单词，可读性强了一丢丢，代码如下：

# -*- coding: utf-8 -*-

import random

puke = [] # 存储扑克牌

num_list = [2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A]

hua_list = [梅花, 红桃, 黑桃, 方块]

sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4, 7: 5, 8: 6, 9: 7, 10: 8, J: 9, Q: 10, K: 11, A: 12,

对子: 15, 顺子: 30, 顺金: 60, 豹子: 100}

count_new_list = [] # 存储玩家分数和排序后排名

count_dic = { } # 存储玩家分数

# 准备52张扑克

for hua in hua_list:

for num in num_list:

a = hua + num

puke.append(a)

player_dic = { 玩家1: [], 玩家2: [], 玩家3: [], 玩家4: [], 玩家5: []}

# 随机给五个玩家发牌

print(len(puke))

for key, value in player_dic.items():

for i in range(3):

plate = random.sample(puke, 3)

player_dic[key] = plate

for i in plate:

puke.remove(i)

print(player_dic)

# 获取玩家的牌型

def paixing(list1):

num = []

huase = []

for data in list1:

huase_type = data[:2]

pai_number = data[2:]

num.append(pai_number)

huase.append(huase_type)

return num, huase

# 对玩家的牌形统计分数

def get_score(num, huase):

base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]

if num[0] == num[1] and num[1] == num[2]:

paixing = 豹子

score = base_count + sort_dic[paixing]

elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[

1] and huase[1] == huase[2]):

paixing = 顺金

score = base_count + sort_dic[paixing]

elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (

huase[0] != huase[

1] or huase[1] != huase[2]):

paixing = 顺子

score = base_count + sort_dic[paixing]

elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (

num[0] == num[2] and num[1] != num[0]):

paixing = 对子

score = base_count + sort_dic[paixing]

else:

score = base_count

return score

if __name__ == __main__:

for key, value in player_dic.items():

num, huase = paixing(value)

# 对数字的牌型进行排序

num = sorted(num)

score = get_score(num, huase)

count_dic[key] = score

print(key + "的牌为：" + str(value))

# 对存储玩家分数的字典进行排序

count_new_list = sorted(zip(count_dic.values(), count_dic.keys()), reverse=True)

print("最终排名：")

for i in range(len(count_new_list)):

print(count_new_list[i][1] + \t, end=)三、总结

我是Python进阶者。本文实际生活中的诈金花游戏，基于Python编程，使用Python基础知识中的列表、字典、函数等，实现了在线诈金花的过程。